Solve 232 ext cm 5 ext mm ext for 15.

$$232 \text{ cm} \div 15$$ $$232 \div 15 = 15 \text{ with a remainder}$$

To find the remainder: $15 \times 15 = 225$.

$$232 - 225 = 7 \text{ cm remainder}$$

So, we have $15 \text{ cm}$ and $7 \text{ cm}$ remaining.

Since $1 \text{ cm} = 10 \text{ mm}$, then $7 \text{ cm} = 7 \times 10 \text{ mm} = 70 \text{ mm}$.
Add this to the original $5 \text{ mm}$:

$$70 \text{ mm} + 5 \text{ mm} = 75 \text{ mm}$$

The length of each piece is the sum of the divided centimeters and millimeters.

$$15 \text{ cm} + 5 \text{ mm} = 15 \text{ cm } 5 \text{ mm}$$

The length of each piece is $\text{15 cm 5 mm}$.