(24m⁴m) ÷ (8m⁶ x 2m⁵)

For the first term, $(24m^n m)$, combine the $m$ terms using the rule $a^x \cdot a^y = a^{x+y}$:

$$24m^n m^1 = 24m^{n+1}$$

For the second term, $(8m^6 \times 2m^5)$, multiply the coefficients and combine the $m$ terms:

$$(8 \times 2) \times (m^6 \times m^5) = 16m^{6+5} = 16m^{11}$$

The expression now becomes:

$$24m^{n+1} \div 16m^{11}$$

Divide the numerical coefficients and the variable terms separately.
Divide the coefficients:

$$\frac{24}{16} = \frac{3 \times 8}{2 \times 8} = \frac{3}{2}$$

Divide the variable terms using the rule $\frac{a^x}{a^y} = a^{x-y}$:

$$\frac{m^{n+1}}{m^{11}} = m^{(n+1)-11} = m^{n-10}$$