Evaluate (2a2)/(c-b) given a=-3, b=2, c=5. Subtract 14346 from 22436 and give the answer in base ten.

$$\frac{18}{3} = 6$$

The evaluated expression is $\boxed{\text{6}}$.

: Subtract $1434_6$ from $2243_6$ and give the answer in base ten.

We perform column subtraction:
$2243_6$

• $1434_6$

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Starting from the rightmost column (units place):
$3 - 4$: We cannot subtract 4 from 3. Borrow from the next column (the 4 in $2243_6$).
The 4 becomes 3, and we add 6 (the base) to the 3, making it $3+6=9$.
Now, $9 - 4 = 5$. So the units digit is 5.

Next column:
$3 - 3 = 0$. So the next digit is 0.

Next column:
$2 - 4$: We cannot subtract 4 from 2. Borrow from the next column (the 2 in $2243_6$).
The 2 becomes 1, and we add 6 to the 2, making it $2+6=8$.
Now, $8 - 4 = 4$. So the next digit is 4.

Next column:
$1 - 1 = 0$. So the leftmost digit is 0.

The result of the subtraction in base 6 is $0405_6$, which is $405_6$.

To convert a number from base $b$ to base 10, we use the formula:

$$(d_n d_{n-1} \dots d_1 d_0)_b = d_n \times b^n + d_{n-1} \times b^{n-1} + \dots + d_1 \times b^1 + d_0 \times b^0$$

For $405_6$:

$$405_6 = 4 \times 6^2 + 0 \times 6^1 + 5 \times 6^0$$ $$= 4 \times 36 + 0 \times 6 + 5 \times 1$$ $$= 144 + 0 + 5$$ $$= 149$$

The answer in base ten is $\boxed{\text{149}}$.