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Solve the 2b + 3a − 6 = 0, 3x + 5x = 0

Mathematics

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Answer

b=3−32a or a=2−23bb = 3 - \frac{3}{2}a \text{ or } a = 2 - \frac{2}{3}b

x=0x = 0

Step-by-step solution

2 steps
  1. Solve the first equation for one variable in terms of the other.

    The equation is 2b+3a−6=02b + 3a - 6 = 0.
    To solve for bb, first isolate the term with bb:

    2b=6−3a2b = 6 - 3a

    Now, divide by 2:

    b=6−3a2b = \frac{6 - 3a}{2}

    This can also be written as:

    b=3−32ab = 3 - \frac{3}{2}a

    Alternatively, to solve for aa:

    3a=6−2b3a = 6 - 2b a=6−2b3a = \frac{6 - 2b}{3} a=2−23ba = 2 - \frac{2}{3}b

    Since the problem asks to "solve the" equation without specifying which variable, expressing one in terms of the other is the complete solution.

  2. Solve the second equation for xx.

    The equation is 3x+5x=03x + 5x = 0.
    Combine the like terms on the left side:

    8x=08x = 0

    Divide both sides by 8:

    x=08x = \frac{0}{8} x=0x = 0

    The solutions are:
    For 2b+3a−6=02b + 3a - 6 = 0: b=3−32a or a=2−23b\boxed{b = 3 - \frac{3}{2}a \text{ or } a = 2 - \frac{2}{3}b}
    For 3x+5x=03x + 5x = 0: x=0\boxed{x = 0}

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