2power5÷2power3

Mathematics

ScanSolve AI Answer

Answer

25÷23=42^5 \div 2^3 = 4

Step-by-step solution

3 steps

To find the value of 25÷232^5 \div 2^3, we use the law of indices which states that when dividing powers with the same base, you subtract the exponents: am÷an=am−na^m \div a^n = a^{m-n}.

  1. Apply the division rule for exponents.

    25÷23=25−32^5 \div 2^3 = 2^{5-3}
  2. Subtract the exponents.

    25−3=222^{5-3} = 2^2
  3. Calculate the value of 222^2.

    22=2×2=42^2 = 2 \times 2 = 4

    The value is:

    25÷23=42^5 \div 2^3 = \boxed{4}
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