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2x + 3y = 16

Mathematics

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Answer

y=−23x+163y = -\frac{2}{3}x + \frac{16}{3}

Step-by-step solution

3 steps

The image shows a linear equation with two variables. Since no specific question was asked, I will express yy in terms of xx.

  1. Start with the given equation.

    2x+3y=162x + 3y = 16

  2. Subtract 2x2x from both sides to isolate the term with yy.

    3y=16−2x3y = 16 - 2x

  3. Divide both sides by 3 to solve for yy.

    y=16−2x3y = \frac{16 - 2x}{3} y=163−23xy = \frac{16}{3} - \frac{2}{3}x

    The equation expressed with yy in terms of xx is:

    y=−23x+163y = -\frac{2}{3}x + \frac{16}{3}
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