3 In line 4 the last number is 7. What would be the last number in Line 7?

Here are the solutions to the pattern problems: 1.1 Line 5: Step 1: Identify the pattern for the sum and the last number. The sum of the first n odd numbers is n^2. The n-th odd number is 2n-1. For Line 5, n=5. Step 2: Calculate the last number and the sum. The last number is 2(5) - 1 = 9. The sum is 5^2 = 25. 1 + 3 + 5 + 7 + 9 = 25 = 5 × 5 The completed line is: Line 5: 1 + 3 + 5 + 7 + 9 = 25 = 5 × 5 1.2 Line 6: Step 1: Identify the pattern for the sum and the last number. For Line 6, n=6. Step 2: Calculate the last number and the sum. The last number is 2(6) - 1 = 11. The sum is 6^2 = 36. 1 + 3 + 5 + 7 + 9 + 11 = 36 = 6 × 6 The completed line is: Line 6: 1 + 3 + 5 + 7 + 9 + 11 = 36 = 6 × 6 1.3 In line 4 the last number is 7. What would be the last number in Line 7? Step 1: Determine the formula for the last number in line n. The last number in Line n is the n-th odd number, which is given by 2n-1. Step 2: Calculate the last number for Line 7. For Line 7, n=7. Last number = 2(7) - 1 = 14 - 1 = 13. The last number in Line 7 would be 13. 1.4 What would all the numbers in Line 12 add up to? Step 1: Determine the formula for the sum of numbers in line n. The sum of the numbers in Line n is n^2. Step 2: Calculate the sum for Line 12. For Line 12, n=12. Sum = 12^2 = 144. All the numbers in Line 12 would add up to 144. 1.5 Use what you have observed above to explain in your own words the total number of first odd numbers. The pattern shows that the sum of the first n consecutive odd numbers is always equal to n squared. For example, the sum of the first 3 odd numbers (1+3+5) is 3^2=9. This relationship holds true for any number of initial odd numbers. Send me the next one 📸