(3x+2)/4-(x-1)/2=1

The least common multiple of 4 and 2 is 4.
Rewrite the second fraction with the common denominator:

$$\frac{x-1}{2} = \frac{2(x-1)}{2 \times 2} = \frac{2(x-1)}{4}$$

The equation becomes:

$$\frac{3x+2}{4} - \frac{2(x-1)}{4} = 1$$

$$\frac{3x+2 - 2x + 2}{4} = 1$$ $$\frac{x+4}{4} = 1$$

$$4 \times \frac{x+4}{4} = 1 \times 4$$ $$x+4 = 4$$

$$x+4-4 = 4-4$$ $$x = 0$$

The solution to the equation is $x=0$.