3x3+4x2-1÷x2+2x+1

Question

3x3+4x2-1÷x2+2x+1

ScanSolve AI Tutor · Accepted Answer

Let's divide ( 3x³ + 4x² − 1 ) by ( x² + 2x + 1 ). Step 1: Set up the division. [ c|c x² + 2x + 1 & 3x³ + 4x² + 0x − 1 ] Step 2: Divide the first term of the dividend by the first term of the divisor: [ (3x³)/(x²) = 3x. ] Step 3: Multiply ( 3x ) by ( x² + 2x + 1 ) and subtract from the dividend. [ 3x · (x² + 2x + 1) = 3x³ + 6x² + 3x. ] Now subtract: [ c|c & 3x³ + 4x² + 0x − 1 & (3x³ + 6x² + 3x) & −2x² − 3x − 1 ] Step 4: Divide the first term of the new dividend by the first term of the divisor: [ (−2x²)/(x²) = −2. ] Step 5: Multiply (−2) by ( x² + 2x + 1 ) and subtract. [ −2 · (x² + 2x + 1) = −2x² − 4x − 2. ] Now subtract: [ c|c & −2x² − 3x − 1 & (−2x² − 4x − 2) & x + 1 ] The quotient is ( 3x − 2 ) and the remainder is ( x + 1 ). Final Answer: [ 3x − 2 + (x + 1)/(x² + 2x + 1) ]

3x3+4x2-1÷x2+2x+1

Answer

Step-by-step solution

Set up the division.

Divide the first term of the dividend by the first term of the divisor

Multiply $3x$ by $x^2 + 2x + 1$ and subtract from the dividend.

Divide the first term of the new dividend by the first term of the divisor

Multiply $-2$ by $x^2 + 2x + 1$ and subtract.

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More Mathematics Questions

3x3+4x2-1÷x2+2x+1

Answer

Step-by-step solution

Set up the division.

Divide the first term of the dividend by the first term of the divisor

Multiply 3x3x3x by x2+2x+1x^2 + 2x + 1x2+2x+1 and subtract from the dividend.

Divide the first term of the new dividend by the first term of the divisor

Multiply −2-2−2 by x2+2x+1x^2 + 2x + 1x2+2x+1 and subtract.

Try one yourself

Still stuck on this one?

More Mathematics Questions

Multiply $3x$ by $x^2 + 2x + 1$ and subtract from the dividend.

Multiply $-2$ by $x^2 + 2x + 1$ and subtract.