SOLVE 4−4x=9−12r

Mathematics

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Answer

x=3r−54x = 3r - \frac{5}{4}

r=x3+512r = \frac{x}{3} + \frac{5}{12}

Step-by-step solution

2 steps

To solve the equation 4−4x=9−12r4 - 4x = 9 - 12r, we can express one variable in terms of the other.

  1. Solve for xx in terms of rr.

    4−4x=9−12r4 - 4x = 9 - 12r

    Subtract 4 from both sides:

    −4x=9−12r−4-4x = 9 - 12r - 4 −4x=5−12r-4x = 5 - 12r

    Divide both sides by -4:

    x=5−12r−4x = \frac{5 - 12r}{-4} x=−54+12r4x = -\frac{5}{4} + \frac{12r}{4} x=−54+3rx = -\frac{5}{4} + 3r
  2. Solve for rr in terms of xx.

    4−4x=9−12r4 - 4x = 9 - 12r

    Subtract 9 from both sides:

    4−4x−9=−12r4 - 4x - 9 = -12r −5−4x=−12r-5 - 4x = -12r

    Divide both sides by -12:

    −5−4x−12=r\frac{-5 - 4x}{-12} = r r=−5−12+−4x−12r = \frac{-5}{-12} + \frac{-4x}{-12} r=512+4x12r = \frac{5}{12} + \frac{4x}{12} r=512+x3r = \frac{5}{12} + \frac{x}{3}

    The solutions are:

    x=3r−54orr=x3+512\boxed{x = 3r - \frac{5}{4}} \quad \text{or} \quad \boxed{r = \frac{x}{3} + \frac{5}{12}}
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