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To solve the equation 4−4x=9−12r, we can express one variable in terms of the other.
Step 1: Solve for x in terms of r.
4−4x=9−12r
Subtract 4 from both sides:
−4x=9−12r−4
−4x=5−12r
Divide both sides by -4:
x=−45−12r
x=−45+412r
x=−45+3r
Step 2: Solve for r in terms of x.
4−4x=9−12r
Subtract 9 from both sides:
4−4x−9=−12r
−5−4x=−12r
Divide both sides by -12:
−12−5−4x=r
r=−12−5+−12−4x
r=125+124x
r=125+3x
The solutions are:
x = 3r - \frac{5{4}} \quad or \quad r = \frac{x{3} + \frac{5}{12}}
What's next?