56÷6 long Division answer please

We need to find how many times 6 goes into 56 without exceeding it.
$6 \times 9 = 54$
$6 \times 10 = 60$ (This is too large)
So, 6 goes into 56 nine times. Write 9 above the 6 in 56.

$9 \times 6 = 54$. Write 54 below 56.

$56 - 54 = 2$. This is the remainder.

The quotient is 9 and the remainder is 2.
So, $56 \div 6 = 9$ with a remainder of 2.

The long division answer is: $\text{9 remainder 2}$