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7(27x6)1/3

Mathematics

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Step-by-step solution

4 steps

Let's simplify this expression using the rules of indices.

The problem is (27x6)13(27x^6)^{\frac{1}{3}}. We need to apply the exponent 13\frac{1}{3} to both the numerical coefficient and the variable term inside the parentheses.

  1. Apply the exponent to each factor inside the parentheses.

    (27x6)13=2713⋅(x6)13(27x^6)^{\frac{1}{3}} = 27^{\frac{1}{3}} \cdot (x^6)^{\frac{1}{3}}
  2. Evaluate 271327^{\frac{1}{3}}.

    This means finding the cube root of 27.
    We know that 3×3×3=273 \times 3 \times 3 = 27.
    So, 2713=327^{\frac{1}{3}} = 3.

  3. Evaluate (x6)13(x^6)^{\frac{1}{3}} using the power of a power rule (am)n=am×n(a^m)^n = a^{m \times n}.

    (x6)13=x6×13=x63=x2(x^6)^{\frac{1}{3}} = x^{6 \times \frac{1}{3}} = x^{\frac{6}{3}} = x^2
  4. Combine the simplified terms.

    3⋅x2=3x23 \cdot x^2 = 3x^2

    The simplified expression is ∗3x2\boxed*{3x^2}.

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