A, B and C are three towns. The bearing of B from A is 150 degrees. The bearing of A from C is 15 degrees. Find the angle CAB.

Here's how to solve this bearing problem:

First, let's determine the angle $\angle CAB$ in the triangle formed by cities A, B, and C.

1. The bearing of B from A is $150^\circ$.
2. The bearing of A from C is $015^\circ$. This means the angle from the North line at C, clockwise to CA, is $15^\circ$.
3. Since the North lines at A and C are parallel, the interior angle between the line CA and the North line at A (measured counter-clockwise from North) is $180^\circ - 15^\circ = 16