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A bus takes 195 minutes to travel a distance of (2x + 30) km at an average speed of (x-20) km/h. Calculate the actual distance travelled. Give your answer in kilometers. (3 marks)

Mathematics

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Answer

182 km\text{182 km}

Step-by-step solution

4 steps

Huu hapa ni utatuzi wa swali la 1:

  1. Badilisha muda kutoka dakika kwenda masaa.

    Muda uliotolewa ni 195 dakika. Ili kubadilisha kwenda masaa, tunagawanya kwa 60:

    T=19560 masaaT = \frac{195}{60} \text{ masaa} T=134 masaaT = \frac{13}{4} \text{ masaa}
  2. Tumia fomula ya umbali, kasi na muda.

    Fomula ni Umbali = Kasi ×\times Muda (D=S×TD = S \times T).
    Tunapewa:
    Umbali D=(2x+30)D = (2x + 30) km
    Kasi S=(x−20)S = (x - 20) km/h
    Muda T=134T = \frac{13}{4} masaa

    Weka thamani hizi kwenye fomula:

    2x+30=(x−20)×1342x + 30 = (x - 20) \times \frac{13}{4}
  3. Tatua mlinganyo ili kupata thamani ya xx.

    Anza kwa kuzidisha pande zote mbili za mlinganyo kwa 4 ili kuondoa sehemu:

    4(2x+30)=13(x−20)4(2x + 30) = 13(x - 20) 8x+120=13x−2608x + 120 = 13x - 260

    Kusanya xx upande mmoja na namba upande mwingine:

    120+260=13x−8x120 + 260 = 13x - 8x 380=5x380 = 5x

    Gawanya kwa 5:

    x=3805x = \frac{380}{5} x=76x = 76
  4. Kokotoa umbali halisi uliosafirishwa.

    Sasa tumia thamani ya x=76x = 76 kwenye usemi wa umbali D=(2x+30)D = (2x + 30) km:

    D=2(76)+30D = 2(76) + 30 D=152+30D = 152 + 30 D=182 kmD = 182 \text{ km}

    Umbali halisi uliosafirishwa ni 182 km\text{182 km}.

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