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A) Calculate the length of BC. b) Calculate the value of angle BAC in degrees, correct to 2 decimal places using tangent tables only. 40. Determine the value of x.

Mathematics

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39.

a) Calculate the length of BC

  1. Use the Pythagorean theorem for the right-angled triangle ABC, where B is the right angle.

    AB2+BC2=AC2AB^2 + BC^2 = AC^2
  2. Substitute the given values AB=13 cmAB = 13 \text{ cm} and AC=85 cmAC = 85 \text{ cm}.

    132+BC2=85213^2 + BC^2 = 85^2 169+BC2=7225169 + BC^2 = 7225
  3. Solve for BC2BC^2.

    BC2=7225−169BC^2 = 7225 - 169 BC2=7056BC^2 = 7056
  4. Calculate BCBC.

    BC=7056BC = \sqrt{7056} BC=84 cmBC = 84 \text{ cm}

    The length of BC is 84 cm\boxed{\text{84 cm}}.

    b) Calculate the value of angle BAC in degrees, correct to 2 decimal places using tangent tables only.

  5. Identify the tangent ratio for angle BAC.

    tan⁡(∠BAC)=OppositeAdjacent=BCAB\tan(\angle BAC) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{BC}{AB}
  6. Substitute the values of BC and AB.

    tan⁡(∠BAC)=8413\tan(\angle BAC) = \frac{84}{13} tan⁡(∠BAC)≈6.461538\tan(\angle BAC) \approx 6.461538
  7. Find the angle whose tangent is approximately 6.461538.

    ∠BAC=arctan⁡(6.461538)\angle BAC = \arctan(6.461538) ∠BAC≈81.2006∘\angle BAC \approx 81.2006^\circ
  8. Round to 2 decimal places.

    ∠BAC≈81.20∘\angle BAC \approx 81.20^\circ

    The value of angle BAC is 81.20∘\boxed{81.20^\circ}.

    40.
    Determine the value of xx.

  9. Use the complementary angle identity cos⁡(θ)=sin⁡(90∘−θ)\cos(\theta) = \sin(90^\circ - \theta).

    Given cos⁡(3x∘)=sin⁡((x−60)∘)\cos(3x^\circ) = \sin((x-60)^\circ), we can rewrite cos⁡(3x∘)\cos(3x^\circ) as sin⁡(90∘−3x∘)\sin(90^\circ - 3x^\circ).
    So, the equation becomes:

    sin⁡(90∘−3x∘)=sin⁡((x−60)∘)\sin(90^\circ - 3x^\circ) = \sin((x-60)^\circ)
  10. Equate the angles since the sine values are equal and xx is acute.

    90−3x=x−6090 - 3x = x - 60
  11. Solve for xx.

    90+60=x+3x90 + 60 = x + 3x 150=4x150 = 4x x=1504x = \frac{150}{4} x=37.5x = 37.5

    The value of xx is 37.5\boxed{37.5}.

    41.

    a) Calculate the amount of money in Ksh, that she obtained after exchanging the foreign currencies.

  12. Calculate the Ksh obtained from Sterling Pounds.

    The bank buys foreign currency.

    Ksh from Sterling Pounds=1580 Sterling Pounds×152 Ksh/Sterling Pound\text{Ksh from Sterling Pounds} = 1580 \text{ Sterling Pounds} \times 152 \text{ Ksh/Sterling Pound} Ksh from Sterling Pounds=239920 Ksh\text{Ksh from Sterling Pounds} = 239920 \text{ Ksh}
  13. Calculate the Ksh obtained from Euros.

    The bank buys foreign currency.

    Ksh from Euros=1205 Euros×125 Ksh/Euro\text{Ksh from Euros} = 1205 \text{ Euros} \times 125 \text{ Ksh/Euro} Ksh from Euros=150625 Ksh\text{Ksh from Euros} = 150625 \text{ Ksh}
  14. Calculate the total amount in Ksh.

    Total Ksh=239920 Ksh+150625 Ksh\text{Total Ksh} = 239920 \text{ Ksh} + 150625 \text{ Ksh} Total Ksh=390545 Ksh\text{Total Ksh} = 390545 \text{ Ksh}

    The businesswoman obtained 390545 Ksh\boxed{390545 \text{ Ksh}}.

    b) Calculate the amount of money, in Ksh that she needed for the exchange.

  15. Calculate the Ksh needed to buy Euros.

    The bank sells foreign currency.

    Ksh for Euros=1250 Euros×128 Ksh/Euro\text{Ksh for Euros} = 1250 \text{ Euros} \times 128 \text{ Ksh/Euro} Ksh for Euros=160000 Ksh\text{Ksh for Euros} = 160000 \text{ Ksh}
  16. Calculate the Ksh needed to buy Sterling Pounds.

    The bank sells foreign currency.

    Ksh for Sterling Pounds=1520 Sterling Pounds×158 Ksh/Sterling Pound\text{Ksh for Sterling Pounds} = 1520 \text{ Sterling Pounds} \times 158 \text{ Ksh/Sterling Pound} Ksh for Sterling Pounds=240160 Ksh\text{Ksh for Sterling Pounds} = 240160 \text{ Ksh}
  17. Calculate the total amount in Ksh needed.

    Total Ksh needed=160000 Ksh+240160 Ksh\text{Total Ksh needed} = 160000 \text{ Ksh} + 240160 \text{ Ksh} Total Ksh needed=400160 Ksh\text{Total Ksh needed} = 400160 \text{ Ksh}

    The trader needed 400160 Ksh\boxed{400160 \text{ Ksh}}.

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