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A container is 6m long, width 3m. Calculate its volume and surface area. Find the surface area of one side of the container.

Mathematics

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Step-by-step solution

2 steps

The problem describes a container with a length of 6 m6 \text{ m} and a width of 3 m3 \text{ m}. From the partial calculation shown (...×3×4 m2... \times 3 \times 4 \text{ m}^2), it can be inferred that the height of the container is 4 m4 \text{ m}. We need to calculate its volume and surface area.

Given:
Length (ll) = 6 m6 \text{ m}
Width (ww) = 3 m3 \text{ m}
Height (hh) = 4 m4 \text{ m}

  1. Calculate the Volume.

    The formula for the volume of a rectangular prism is V=l×w×hV = l \times w \times h.

    V=6 m×3 m×4 mV = 6 \text{ m} \times 3 \text{ m} \times 4 \text{ m} V=18 m2×4 mV = 18 \text{ m}^2 \times 4 \text{ m} V=72 m3V = 72 \text{ m}^3
  2. Calculate the Surface Area.

    The formula for the surface area of a rectangular prism is A=2(lw+lh+wh)A = 2(lw + lh + wh).

    A=2((6 m×3 m)+(6 m×4 m)+(3 m×4 m))A = 2((6 \text{ m} \times 3 \text{ m}) + (6 \text{ m} \times 4 \text{ m}) + (3 \text{ m} \times 4 \text{ m})) A=2(18 m2+24 m2+12 m2)A = 2(18 \text{ m}^2 + 24 \text{ m}^2 + 12 \text{ m}^2) A=2(54 m2)A = 2(54 \text{ m}^2) A=108 m2A = 108 \text{ m}^2

    The volume of the container is 72 m3\boxed{72 \text{ m}^3}.
    The surface area of the container is 108 m2\boxed{108 \text{ m}^2}.

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