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A cubical tank has a side of 4 m and is full of water. How much water does it contain in litres?

Mathematics

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9. A farmer has 96 m of wire, exactly enough to fence a square plot once. What is the area of the plot?

  1. Find the side length of the square plot.

    The length of the wire represents the perimeter of the square.

    Perimeter=4×side\text{Perimeter} = 4 \times \text{side} 96 m=4×side96 \text{ m} = 4 \times \text{side} side=96 m4=24 m\text{side} = \frac{96 \text{ m}}{4} = 24 \text{ m}
  2. Calculate the area of the square plot.

    Area=side2\text{Area} = \text{side}^2 Area=(24 m)2=576 m2\text{Area} = (24 \text{ m})^2 = 576 \text{ m}^2

    The correct option is A).

    A) 576 m2\boxed{\text{A) } 576 \text{ m}^2}

    10. Mary and Asha share 18 kg of maize flour. Mary receives 4 kg more than Asha. How much does each receive?

  3. Set up equations based on the given information.

    Let Asha's share be AA kg.
    Let Mary's share be MM kg.

    A+M=18(Equation 1)A + M = 18 \quad (\text{Equation 1}) M=A+4(Equation 2)M = A + 4 \quad (\text{Equation 2})
  4. Substitute Equation 2 into Equation 1 and solve for AA.

    A+(A+4)=18A + (A + 4) = 18 2A+4=182A + 4 = 18 2A=18−42A = 18 - 4 2A=142A = 14 A=142=7 kgA = \frac{14}{2} = 7 \text{ kg}
  5. Substitute the value of AA back into Equation 2 to find MM.

    M=7+4=11 kgM = 7 + 4 = 11 \text{ kg}

    So, Mary receives 11 kg and Asha receives 7 kg.
    The correct option is C).

    C) Mary 11 kg, Asha 7 kg\boxed{\text{C) Mary 11 kg, Asha 7 kg}}

    11. A hall can accommodate at most 320 learners. If x represents the number of learners in the hall, which inequality is correct?

  6. Interpret the phrase "at most 320 learners".

    This means the number of learners (xx) can be 320 or any number less than 320.

    x≤320x \le 320

    The correct option is B).

    B) x≤320\boxed{\text{B) } x \le 320}

    12. A cylindrical tank has radius 4 cm and height 6 cm. What is its volume? Take π=3.142\pi = 3.142.

  7. Write the formula for the volume of a cylinder.

    V=πr2hV = \pi r^2 h
  8. Substitute the given values into the formula.

    V=3.142×(4 cm)2×6 cmV = 3.142 \times (4 \text{ cm})^2 \times 6 \text{ cm} V=3.142×16 cm2×6 cmV = 3.142 \times 16 \text{ cm}^2 \times 6 \text{ cm}
  9. Calculate the volume.

    V=3.142×96 cm3V = 3.142 \times 96 \text{ cm}^3 V=301.632 cm3V = 301.632 \text{ cm}^3

    Rounding to one decimal place, V≈301.6 cm3V \approx 301.6 \text{ cm}^3.
    The correct option is A).

    A) 301.6 cm3\boxed{\text{A) } 301.6 \text{ cm}^3}

    13. A 13 m ladder rests against a vertical wall. Its foot is 5 m from the wall. How high up the wall does it reach?

  10. Recognize that this forms a right-angled triangle.

    The ladder is the hypotenuse (cc), the distance from the wall is one leg (aa), and the height up the wall is the other leg (bb).
    Apply the Pythagorean theorem: a2+b2=c2a^2 + b^2 = c^2.

    52+b2=1325^2 + b^2 = 13^2
  11. Calculate the squares.

    25+b2=16925 + b^2 = 169
  12. Solve for b2b^2.

    b2=169−25b^2 = 169 - 25 b2=144b^2 = 144
  13. Find the value of bb.

    b=144b = \sqrt{144} b=12 mb = 12 \text{ m}

    The correct option is C).

    C) 12 m\boxed{\text{C) } 12 \text{ m}}

    14. A rectangular garden is 18 m long and 11 m wide. What is its area?

  14. Write the formula for the area of a rectangle.

    Area=length×width\text{Area} = \text{length} \times \text{width}
  15. Substitute the given values.

    Area=18 m×11 m\text{Area} = 18 \text{ m} \times 11 \text{ m}
  16. Calculate the area.

    Area=198 m2\text{Area} = 198 \text{ m}^2

    The correct option is B).

    B) 198 m2\boxed{\text{B) } 198 \text{ m}^2}

    15. Calculate the area of a parallelogram whose base is 15 cm and perpendicular height is 8 cm.

  17. Write the formula for the area of a parallelogram.

    Area=base×height\text{Area} = \text{base} \times \text{height}
  18. Substitute the given values.

    Area=15 cm×8 cm\text{Area} = 15 \text{ cm} \times 8 \text{ cm}
  19. Calculate the area.

    Area=120 cm2\text{Area} = 120 \text{ cm}^2

    The correct option is C).

    C) 120 cm2\boxed{\text{C) } 120 \text{ cm}^2}

    16. A cubical tank has a side of 4 m and is full of water. How much water does it contain in litres?

  20. Calculate the volume of the cubical tank in cubic meters.

    Volume=side3\text{Volume} = \text{side}^3 Volume=(4 m)3=64 m3\text{Volume} = (4 \text{ m})^3 = 64 \text{ m}^3
  21. Convert the volume from cubic meters to litres.

    (Note: 1 m3=1000 litres1 \text{ m}^3 = 1000 \text{ litres})

    Volume in litres=64 m3×1000 litres/m3\text{Volume in litres} = 64 \text{ m}^3 \times 1000 \text{ litres/m}^3 Volume in litres=64,000 litres\text{Volume in litres} = 64,000 \text{ litres}

    The correct option is C).

    C) 64,000 litres\boxed{\text{C) } 64,000 \text{ litres}}
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