A) Express 48 and 60 as a product of their prime factors. b) Hence, find the LCM and GCD of 48 and 60.

The prime factorization of 48 is $\boxed{2^4 \times 3}$ and for 60 is $\boxed{2^2 \times 3 \times 5}$.

b) Hence, find the LCM and GCD of 48 and 60.

$48 = 2^4 \times 3^1 \times 5^0$
$60 = 2^2 \times 3^1 \times 5^1$

For GCD, take the lowest power of each common prime factor.
Common prime factors are 2 and 3.
Lowest power of 2 is $2^2$.
Lowest power of 3 is $3^1$.

For LCM, take the highest power of all prime factors present in either number.
Highest power of 2 is $2^4$.
Highest power of 3 is $3^1$.
Highest power of 5 is $5^1$.

The GCD of 48 and 60 is $\boxed{12}$ and the LCM is $\boxed{240}$.

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