A farmer buys 2 bags of fertilizer and 4 bags of maize seeds for Sh. 1400. Another farmer buys 3 bags of fertilizer and 3 bags of maize seeds for Sh. 1500. What is the price of 2 bags of fertilizer an

Let $x$ be the price of one bag of fertilizer and $y$ be the price of one bag of maize seed.
From the problem statement, we have two equations:
For 2 bags of fertilizer and 4 bags of maize seeds costing Sh. 1400:

$$2x + 4y = 1400 \quad (1)$$

For 3 bags of fertilizer and 3 bags of maize seeds costing Sh. 1500:

$$3x + 3y = 1500 \quad (2)$$

Divide equation (1) by 2:

$$x + 2y = 700 \quad (3)$$

Divide equation (2) by 3:

$$x + y = 500 \quad (4)$$

Subtract equation (4) from equation (3):

$$(x + 2y) - (x + y) = 700 - 500$$ $$y = 200$$

Substitute $y = 200$ into equation (4):

$$x + 200 = 500$$ $$x = 500 - 200$$ $$x = 300$$

So, one bag of fertilizer costs Sh. 300 and one bag of maize seed costs Sh. 200.

We need to find the value of $2x + 3y$.

$$2x + 3y = 2(300) + 3(200)$$ $$2x + 3y = 600 + 600$$ $$2x + 3y = 1200$$

The price of 2 bags of fertilizer and 3 bags of maize seeds is:

$$\mathbf{Sh. 1200}$$