A flight departs at 9:20 PM and arrives at 3:50 AM the next day. If the distance flown was 8,046 km, what was the average speed of the flight in km/h, rounded to the nearest whole number?

Time from 9:20 PM to 12:00 AM (midnight) = 2 hours 40 minutes.
Time from 12:00 AM to 3:50 AM = 3 hours 50 minutes.
Total time = (2 hours 40 minutes) + (3 hours 50 minutes) = 5 hours 90 minutes = 6 hours 30 minutes.
Convert total time to hours: $6 \text{ hours} + \frac{30}{60} \text{ hours} = 6.5 \text{ hours}$.

The distance is given as $8,0467 \text{ km}$. Assuming this is a typo and meant to be $8046 \text{ km}$ (as $80467 \text{ km}$ would imply an extremely high, non-commercial flight speed).