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A guardian gave a child some money. The child used 2/5 of the money to buy sugar and 5/9 of the remaining money to buy rice. If the child deposited the rest of the money, which was UGX 40,000, find th

Mathematics

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Answer

b
1032

Step-by-step solution

9 steps

Here are the solutions to the questions:

Part a· 7 steps

How you used the money he gave you.

  1. Let the total money given by the guardian be MM.

    Money used for sugar =25M= \frac{2}{5}M.

  2. Calculate the remaining money after buying sugar.

    Remaining money =M−25M=35M= M - \frac{2}{5}M = \frac{3}{5}M.

  3. Calculate the money used for buying rice.

    Money for rice =59= \frac{5}{9} of the remaining money.
    Money for rice =59×35M=1545M=13M= \frac{5}{9} \times \frac{3}{5}M = \frac{15}{45}M = \frac{1}{3}M.

  4. Calculate the total fraction of money spent on sugar and rice.

    Total fraction spent =25M+13M=615M+515M=1115M= \frac{2}{5}M + \frac{1}{3}M = \frac{6}{15}M + \frac{5}{15}M = \frac{11}{15}M.

  5. Determine the fraction of money deposited.

    The money deposited is the balance.
    Fraction deposited =M−1115M=415M= M - \frac{11}{15}M = \frac{4}{15}M.

  6. Calculate the total money given, since UGX 40,000 was deposited.

    We know that 415M=UGX 40,000\frac{4}{15}M = \text{UGX } 40,000.

    M=40,000×154M = 40,000 \times \frac{15}{4} M=10,000×15M = 10,000 \times 15 M=150,000M = 150,000

    The total money given was UGX 150,000.

  7. Show the breakdown of how the money was used.

    Money for sugar =25×150,000=UGX 60,000= \frac{2}{5} \times 150,000 = \text{UGX } 60,000.
    Money for rice =13×150,000=UGX 50,000= \frac{1}{3} \times 150,000 = \text{UGX } 50,000.
    Money deposited =UGX 40,000= \text{UGX } 40,000.
    Total spent and deposited =60,000+50,000+40,000=UGX 150,000= 60,000 + 50,000 + 40,000 = \text{UGX } 150,000.

Part b1032

How you obtained the correct pin.

  1. Convert the given code 78 (base 10) to base four.

    Divide 78 by 4 and record the remainders.

    78÷4=19 remainder 278 \div 4 = 19 \text{ remainder } 2 19÷4=4 remainder 319 \div 4 = 4 \text{ remainder } 3 4÷4=1 remainder 04 \div 4 = 1 \text{ remainder } 0 1÷4=0 remainder 11 \div 4 = 0 \text{ remainder } 1
  2. Read the remainders from bottom to top to get the base four number.

    The PIN is 103241032_4.
    The correct PIN is 1032\boxed{1032}.

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