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A local authority divided 630 000 m² of land into plots each with an area of 560 m². How many plot they fit m 15% of the land is set a side and park?

Mathematics

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Answer

2,876,400 Springbok\text{2,876,400 Springbok}

Step-by-step solution

3 steps

Question 2:
A game reserve has an area of 38,352 ha38,352 \text{ ha}. The number of Springbok in the game reserve is restricted to 75 ha75 \text{ ha}. Calculate the number of Springbok in the game reserve.

Assumption: The phrase "restricted to 75 ha75 \text{ ha}" is interpreted as a density of 75 Springbok per hectare (75 Springbok/ha75 \text{ Springbok/ha}). This is a common way to express animal population limits in relation to land area, despite the unusual phrasing.

  1. Identify the total area of the game reserve and the assumed Springbok density.

    Total area of game reserve =38,352 ha= 38,352 \text{ ha}
    Springbok density (assumed) =75 Springbok/ha= 75 \text{ Springbok/ha}

  2. Calculate the total number of Springbok by multiplying the total area by the density.

    Number of Springbok=Total Area×Springbok Density\text{Number of Springbok} = \text{Total Area} \times \text{Springbok Density} Number of Springbok=38,352 ha×75Springbokha\text{Number of Springbok} = 38,352 \text{ ha} \times 75 \frac{\text{Springbok}}{\text{ha}}
  3. Perform the multiplication.

    Number of Springbok=2,876,400\text{Number of Springbok} = 2,876,400

    The total number of Springbok in the reserve is 2,876,400 Springbok\text{2,876,400 Springbok}.

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