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A man walks 5m due north, then 5m due east. What is the distance from the starting point to the end point?

Mathematics

ScanSolve AI Answer

Answer

9 m\text{9 m}

Step-by-step solution

4 steps

Here's how to solve this problem:

The problem describes a right-angled triangle where:

  • The height of the pole is one leg, a=12a = 12 m.
  • The length of the wire is the hypotenuse, c=15c = 15 m.
  • The distance from the pole to the point where the wire is fixed to the ground is the other leg, b=xb = x.
  1. Apply the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (cc) is equal to the sum of the squares of the other two sides (aa and bb).

    a2+b2=c2a^2 + b^2 = c^2

    Substitute the given values:

    122+x2=15212^2 + x^2 = 15^2
  2. Calculate the squares of the known values.

    144+x2=225144 + x^2 = 225
  3. Isolate x2x^2 by subtracting 144 from both sides of the equation.

    x2=225−144x^2 = 225 - 144 x2=81x^2 = 81
  4. Take the square root of both sides to find the value of xx.

    x=81x = \sqrt{81} x=9x = 9

    The distance from the pole to the point where the wire is fixed to the ground is 9 m\boxed{\text{9 m}}.

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