We read your photo as:

A measuring tape is stated to be 50 m long, but its actual length is 50.023 m. If a distance measured with this tape is 725 m, what is the corrected distance?

Mathematics

ScanSolve AI Answer

Answer

725.3335 m\text{725.3335 m}

Step-by-step solution

3 steps
  1. Identify the given values.

    • Measured distance (LmL_m) = 725 m725 \text{ m}
    • Designated length of the tape (LL) = 50 m50 \text{ m}
    • Actual length of the tape (L′L') = 50.023 m50.023 \text{ m}
  2. Apply the formula for corrected distance.

    The formula for the corrected distance (LcL_c) is:

    Lc=Lm×L′LL_c = L_m \times \frac{L'}{L}
  3. Substitute the values and calculate the corrected distance.

    Lc=725 m×50.023 m50 mL_c = 725 \text{ m} \times \frac{50.023 \text{ m}}{50 \text{ m}} Lc=725×1.00046 mL_c = 725 \times 1.00046 \text{ m} Lc=725.3335 mL_c = 725.3335 \text{ m}

    The true length of the survey data is:

    725.3335 m\text{725.3335 m}
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp