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A photograph is 6m long and 5m wide. If the photograph is enlarged by a linear scale factor of 2, what is the area of the enlarged photograph?

Mathematics

ScanSolve AI Answer

Answer

4

Step-by-step solution

5 steps
  1. Identify the dimensions of the original photograph and calculate its area.

    The original photograph has a length (LoriginalL_{original}) of 6 m and a width (WoriginalW_{original}) of 5 m.
    The area of the original photograph (AoriginalA_{original}) is:

    Aoriginal=Loriginal×Woriginal=6 m×5 m=30 m2A_{original} = L_{original} \times W_{original} = 6 \text{ m} \times 5 \text{ m} = 30 \text{ m}^2

    This matches the student's calculation of A=6×5=30A = 6 \times 5 = 30.

  2. Determine the linear scale factor from the student's previous work.

    From the student's work in part 'a', it is assumed that the linear scale factor (kk) is 2.

    k=2k = 2
  3. Calculate the dimensions of the enlarged photograph using the linear scale factor.

    New Length (LenlargedL_{enlarged}) =Loriginal×k=6 m×2=12 m= L_{original} \times k = 6 \text{ m} \times 2 = 12 \text{ m}
    New Width (WenlargedW_{enlarged}) =Woriginal×k=5 m×2=10 m= W_{original} \times k = 5 \text{ m} \times 2 = 10 \text{ m}
    This matches the student's calculation for the enlarged width.

  4. Calculate the area of the enlarged photograph.

    The area of the enlarged photograph (AenlargedA_{enlarged}) is:

    Aenlarged=Lenlarged×Wenlarged=12 m×10 m=120 m2A_{enlarged} = L_{enlarged} \times W_{enlarged} = 12 \text{ m} \times 10 \text{ m} = 120 \text{ m}^2
  5. Calculate the area scale factor (ASF).

    The area scale factor is the ratio of the area of the enlarged photograph to the area of the original photograph.

    ASF=AenlargedAoriginal=120 m230 m2=4\text{ASF} = \frac{A_{enlarged}}{A_{original}} = \frac{120 \text{ m}^2}{30 \text{ m}^2} = 4

    Alternatively, the area scale factor is the square of the linear scale factor (k2k^2).

    ASF=k2=22=4\text{ASF} = k^2 = 2^2 = 4

    The area scale factor is 4.

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