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A symmetric distribution has a median of 10 and an IQR of 10. What is the value of the first quartile (Q1)?

Mathematics

ScanSolve AI Answer

Answer

5\text{5}

Step-by-step solution

4 steps
  1. Identify the given information.

    The distribution is symmetric.
    The Interquartile Range (IQR) is 10.
    The Median is 10.

  2. Recall the properties of a symmetric distribution.

    For a symmetric distribution, the median is exactly halfway between the first quartile (Q1Q1) and the third quartile (Q3Q3). This means the distance from Q1Q1 to the median is equal to the distance from the median to Q3Q3.
    Mathematically, this can be expressed as:

    Median−Q1=Q3−Median\text{Median} - Q1 = Q3 - \text{Median}

    The Interquartile Range (IQR) is defined as Q3−Q1Q3 - Q1.
    For a symmetric distribution, the distance from Q1Q1 to the median is half of the IQR:

    Median−Q1=IQR2\text{Median} - Q1 = \frac{\text{IQR}}{2}
  3. Substitute the given values into the formula.

    We are given IQR=10\text{IQR} = 10 and Median=10\text{Median} = 10.

    10−Q1=10210 - Q1 = \frac{10}{2} 10−Q1=510 - Q1 = 5
  4. Solve for Q1Q1.

    Q1=10−5Q1 = 10 - 5 Q1=5Q1 = 5

    The First Quartile (Q1Q1) is 5. This corresponds to the first option provided.

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