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A vendor sells a exercise book and 3 rulers for 190. Another vendor sells a expense book and 5 rulers for 250. Find the cost of one ruler using the elimination method.

Mathematics

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Answer

Sh. 30\text{Sh. } 30

Step-by-step solution

4 steps

Huu ni mfumo wa milinganyo miwili. Tutatumia njia ya kuondoa (elimination method) kutatua.

  1. Andika milinganyo.

    Tutaweka xx kuwa gharama ya kitabu kimoja cha mazoezi na yy kuwa gharama ya rula moja.
    Kutoka taarifa ya kwanza:

    x+3y=190(Mlinganyo 1)x + 3y = 190 \quad \text{(Mlinganyo 1)}

    Kutoka taarifa ya pili:

    x+5y=250(Mlinganyo 2)x + 5y = 250 \quad \text{(Mlinganyo 2)}
  2. Ondoa mlinganyo 1 kutoka mlinganyo 2.

    Ili kuondoa xx, tutatoa Mlinganyo 1 kutoka Mlinganyo 2.

    (x+5y)−(x+3y)=250−190(x + 5y) - (x + 3y) = 250 - 190 x+5y−x−3y=60x + 5y - x - 3y = 60 2y=602y = 60
  3. Tatua kwa yy.

    Gawanya pande zote mbili kwa 2 ili kupata thamani ya yy.

    2y2=602\frac{2y}{2} = \frac{60}{2} y=30y = 30
  4. Toa jibu.

    Gharama ya rula moja ni shilingi 30.

    Gharama ya rula moja ni:

    Sh. 30\text{Sh. } 30
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