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Here are the solutions to the addition problems:
1.
Step 1: Write the expression for addition.
8ab+(−5ab)+3ab+(−ab)
Step 2: Combine the coefficients of the like terms.
(8−5+3−1)ab=(3+3−1)ab=(6−1)ab=5ab
The sum is 5ab.
2.
Step 1: Write the expression for addition.
7x+(−3x)+5x+(−x)+(−2x)
Step 2: Combine the coefficients of the like terms.
(7−3+5−1−2)x=(4+5−1−2)x=(9−1−2)x=(8−2)x=6x
The sum is 6x.
3.
Step 1: Write the expression for addition, grouping like terms.
(3a−4b+4c)+(2a+3b−8c)+(a−6b+c)
=(3a+2a+a)+(−4b+3b−6b)+(4c−8c+c)
Step 2: Combine the coefficients for each variable.
=(3+2+1)a+(−4+3−6)b+(4−8+1)c
=6a+(−1−6)b+(−4+1)c
=6a−7b−3c
The sum is 6a−7b−3c.
4.
Step 1: Write the expression for addition, grouping like terms.
(5x−8y+2z)+(3z−4y−2x)+(6y−z−x)+(3x−2z−3y)
=(5x−2x−x+3x)+(−8y−4y+6y−3y)+(2z+3z−z−2z)
Step 2: Combine the coefficients for each variable.
=(5−2−1+3)x+(−8−4+6−3)y+(2+3−1−2)z
=(3−1+3)x+(−12+6−3)y+(5−1−2)z
=(2+3)x+(−6−3)y+(4−2)z
=5x−9y+2z
The sum is 5x−9y+2z.
5.
Step 1: Write the expression for addition, grouping like terms.
(6ax−2by+3cz)+(6by−11ax−cz)+(10cz−2ax−3by)
=(6ax−11ax−2ax)+(−2by+6by−3by)+(3cz−cz+10cz)
Step 2: Combine the coefficients for each variable.
=(6−11−2)ax+(−2+6−3)by+(3−1+10)cz
=(−5−2)ax+(4−3)by+(2+10)cz
=−7ax+by+12cz
The sum is −7ax+by+12cz.
6.
Step 1: Write the expression for addition, grouping like terms by degree.
(2x3−9x2+8)+(3x2−6x−5)+(7x3−10x+1)+(3+2x−5x2−4x3)
=(2x3+7x3−4x3)+(−9x2+3x2−5x2)+(−6x−10x+2x)+(8−5+1+3)
Step 2: Combine the coefficients for each term.
=(2+7−4)x3+(−9+3−5)x2+(−6−10+2)x+(8−5+1+3)
=(9−4)x3+(−6−5)x2+(−16+2)x+(3+1+3)
=5x3−11x2−14x+7
The sum is 5x3−11x2−14x+7.
7.
Step 1: Write the expression for addition, grouping like terms.
(6p+4q−r+3)+(2r−5p−6)+(11q−7p+2r−1)+(2q−3r+4)
=(6p−5p−7p)+(4q+11q+2q)+(−r+2r+2r−3r)+(3−6−1+4)
Step 2: Combine the coefficients for each variable and constant.
=(6−5−7)p+(4+11+2)q+(−1+2+2−3)r+(3−6−1+4)
=(1−7)p+(15+2)q+(1+2−3)r+(−3−1+4)
=−6p+17q+(3−3)r+(−4+4)
=−6p+17q+0r+0
=−6p+17q
The sum is −6p+17q.
8.
Step 1: Write the expression for addition, grouping like terms.
(4x2−7xy+4y2−3)+(5+6y2−8xy+x2)+(6−2xy+2x2−5y2)
=(4x2+x2+2x2)+(−7xy−8xy−2xy)+(4y2+6y2−5y2)+(−3+5+6)
Step 2: Combine the coefficients for each term.
=(4+1+2)x2+(−7−8−2)xy+(4+6−5)y2+(−3+5+6)
=7x2+(−15−2)xy+(10−5)y2+(2+6)
=7x2−17xy+5y2+8
The sum is 7x2−17xy+5y2+8.
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