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Alexis had 5/12 of a cake. She ate 4/7 of the remaining cake. How much of the original cake did Alexis eat? Bookyeuwaa baked 542 meat pies and planned to serve 7 friends equally. How many meat pies wi

Mathematics

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4.

  1. Identify the initial amount of cake.

    The initial amount of cake in the fridge was 512\frac{5}{12}.

  2. Determine the fraction of the cake Alexis ate.

    Alexis ate 47\frac{4}{7} of the leftover cake, which is 512\frac{5}{12}. To find out how much she ate, we multiply these fractions.

    Amount Alexis ate=47×512\text{Amount Alexis ate} = \frac{4}{7} \times \frac{5}{12}
  3. Calculate the amount Alexis ate.

    47×512=4×57×12=2084\frac{4}{7} \times \frac{5}{12} = \frac{4 \times 5}{7 \times 12} = \frac{20}{84}

    Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 4.

    20÷484÷4=521\frac{20 \div 4}{84 \div 4} = \frac{5}{21}

    Alexis had 521\frac{5}{21} of the original cake.

    The amount of cake Alexis had was 521\boxed{\frac{5}{21}}.

    5.
    This question asks about "donuts" but the context is about "meat pies". Assuming "donuts" is a typo and it should be "meat pies", we will calculate the number of meat pies Bookyeuwaa is left with.

  4. Identify the total number of meat pies.

    Bookyeuwaa baked 542 meat pies.

  5. Determine how many friends will be served.

    She planned to serve 7 friends equally.

  6. Calculate the number of pies each friend receives and the remainder for Bookyeuwaa.

    We divide the total pies by the number of friends:

    542÷7542 \div 7 542=7×77+3542 = 7 \times 77 + 3

    This means each of the 7 friends will receive 77 meat pies, and there will be a remainder of 3 meat pies.
    Bookyeuwaa will be left with the remainder.

    Bookyeuwaa will be left with 3 meat pies\boxed{3 \text{ meat pies}}.

    6.

  7. Find the quotient of 88,668 and 9.

    To find the quotient, we divide 88,668 by 9.

    88,668÷9=9,85288,668 \div 9 = 9,852

    The quotient of 88,668 and 9 is 9,852\boxed{9,852}.

    7a.

  8. Simplify the fractions.

    The given expression is 45+39\frac{4}{5} + \frac{3}{9}.
    The fraction 39\frac{3}{9} can be simplified by dividing both the numerator and the denominator by 3:

    39=3÷39÷3=13\frac{3}{9} = \frac{3 \div 3}{9 \div 3} = \frac{1}{3}

    So the expression becomes:

    45+13\frac{4}{5} + \frac{1}{3}
  9. Find a common denominator.

    The least common multiple of 5 and 3 is 15.
    Convert each fraction to an equivalent fraction with a denominator of 15.
    For 45\frac{4}{5}:

    45=4×35×3=1215\frac{4}{5} = \frac{4 \times 3}{5 \times 3} = \frac{12}{15}

    For 13\frac{1}{3}:

    13=1×53×5=515\frac{1}{3} = \frac{1 \times 5}{3 \times 5} = \frac{5}{15}
  10. Add the fractions.

    Now add the fractions with the common denominator:

    1215+515=12+515=1715\frac{12}{15} + \frac{5}{15} = \frac{12 + 5}{15} = \frac{17}{15}

    The fraction 1715\frac{17}{15} can also be written as a mixed number:

    12151 \frac{2}{15}

    The simplified sum is 1715\boxed{\frac{17}{15}} or 1215\boxed{1 \frac{2}{15}}.

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