Derive the Almighty formula explaining each steps in details

Mathematics

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Answer

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Step-by-step solution

8 steps

The "Almighty formula" refers to the quadratic formula, which solves equations of the form ax2+bx+c=0ax^2 + bx + c = 0.

  1. Start with the standard quadratic equation.

    ax2+bx+c=0ax^2 + bx + c = 0
  2. Divide the entire equation by aa (assuming a≠0a \neq 0) to make the coefficient of x2x^2 equal to 1.

    ax2a+bxa+ca=0a\frac{ax^2}{a} + \frac{bx}{a} + \frac{c}{a} = \frac{0}{a} x2+bax+ca=0x^2 + \frac{b}{a}x + \frac{c}{a} = 0
  3. Move the constant term ca\frac{c}{a} to the right side of the equation.

    x2+bax=−cax^2 + \frac{b}{a}x = -\frac{c}{a}
  4. Complete the square on the left side.

    To do this, add (12⋅coefficient of x)2(\frac{1}{2} \cdot \text{coefficient of } x)^2 to both sides. The coefficient of xx is ba\frac{b}{a}, so we add (12⋅ba)2=(b2a)2=b24a2(\frac{1}{2} \cdot \frac{b}{a})^2 = (\frac{b}{2a})^2 = \frac{b^2}{4a^2} to both sides.

    x2+bax+(b2a)2=−ca+(b2a)2x^2 + \frac{b}{a}x + \left(\frac{b}{2a}\right)^2 = -\frac{c}{a} + \left(\frac{b}{2a}\right)^2 x2+bax+b24a2=−ca+b24a2x^2 + \frac{b}{a}x + \frac{b^2}{4a^2} = -\frac{c}{a} + \frac{b^2}{4a^2}
  5. Factor the left side as a perfect square.

    (x+b2a)2=−ca+b24a2\left(x + \frac{b}{2a}\right)^2 = -\frac{c}{a} + \frac{b^2}{4a^2}
  6. Combine the terms on the right side by finding a common denominator, which is 4a24a^2.

    (x+b2a)2=−ca⋅4a4a+b24a2\left(x + \frac{b}{2a}\right)^2 = -\frac{c}{a} \cdot \frac{4a}{4a} + \frac{b^2}{4a^2} (x+b2a)2=−4ac4a2+b24a2\left(x + \frac{b}{2a}\right)^2 = -\frac{4ac}{4a^2} + \frac{b^2}{4a^2} (x+b2a)2=b2−4ac4a2\left(x + \frac{b}{2a}\right)^2 = \frac{b^2 - 4ac}{4a^2}
  7. Take the square root of both sides.

    Remember to include both positive and negative roots.

    (x+b2a)2=±b2−4ac4a2\sqrt{\left(x + \frac{b}{2a}\right)^2} = \pm\sqrt{\frac{b^2 - 4ac}{4a^2}} x+b2a=±b2−4ac4a2x + \frac{b}{2a} = \pm\frac{\sqrt{b^2 - 4ac}}{\sqrt{4a^2}} x+b2a=±b2−4ac2ax + \frac{b}{2a} = \pm\frac{\sqrt{b^2 - 4ac}}{2a}
  8. Isolate xx by subtracting b2a\frac{b}{2a} from both sides.

    x=−b2a±b2−4ac2ax = -\frac{b}{2a} \pm \frac{\sqrt{b^2 - 4ac}}{2a} x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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