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An arc of length 22 cm subtends an angle 0 at the centre of a circle. If the radius of the circle is 15 cm, find the value of 0.

Mathematics

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Answer

D

Step-by-step solution

11 steps

10. Volume of water in a cylindrical tin

  1. Calculate the radius of the cylindrical tin.

    The diameter is 13.2 cm13.2 \text{ cm}.

    r=diameter2=13.2 cm2=6.6 cmr = \frac{\text{diameter}}{2} = \frac{13.2 \text{ cm}}{2} = 6.6 \text{ cm}

    The height of the tin is h=20 cmh = 20 \text{ cm}.

  2. Calculate the total volume of the cylindrical tin.

    The formula for the volume of a cylinder is V=πr2hV = \pi r^2 h.

    Vtotal=π(6.6 cm)2(20 cm)V_{total} = \pi (6.6 \text{ cm})^2 (20 \text{ cm}) Vtotal=π(43.56 cm2)(20 cm)V_{total} = \pi (43.56 \text{ cm}^2) (20 \text{ cm}) Vtotal=871.2π cm3V_{total} = 871.2 \pi \text{ cm}^3
  3. Calculate the volume of water.

    The tin is half-filled with water.

    Vwater=12VtotalV_{water} = \frac{1}{2} V_{total} Vwater=12(871.2π cm3)V_{water} = \frac{1}{2} (871.2 \pi \text{ cm}^3) Vwater=435.6π cm3V_{water} = 435.6 \pi \text{ cm}^3

    The correct option is D.

    D. 435.6π cm3\boxed{\text{D. } 435.6\pi \text{ cm}^3}

    11. Angle subtended by an arc

  4. Use the arc length formula to find the angle in radians.

    The formula for arc length is L=rθL = r\theta, where LL is the arc length, rr is the radius, and θ\theta is the angle in radians.
    Given L=22 cmL = 22 \text{ cm} and r=15 cmr = 15 \text{ cm}.

    22 cm=(15 cm)θ22 \text{ cm} = (15 \text{ cm}) \theta θ=2215 radians\theta = \frac{22}{15} \text{ radians}
  5. Convert the angle from radians to degrees.

    To convert radians to degrees, multiply by 180∘π\frac{180^\circ}{\pi}. We are given to take π=227\pi = \frac{22}{7}.

    θdegrees=2215×180∘227\theta_{\text{degrees}} = \frac{22}{15} \times \frac{180^\circ}{\frac{22}{7}} θdegrees=2215×180∘×722\theta_{\text{degrees}} = \frac{22}{15} \times \frac{180^\circ \times 7}{22} θdegrees=115×180∘×7\theta_{\text{degrees}} = \frac{1}{15} \times 180^\circ \times 7 θdegrees=12∘×7\theta_{\text{degrees}} = 12^\circ \times 7 θdegrees=84∘\theta_{\text{degrees}} = 84^\circ

    The correct option is C.

    C. 84∘\boxed{\text{C. } 84^\circ}

    12. Common difference of an Arithmetic Progression

  6. Write down the formulas for the terms of an Arithmetic Progression (AP).

    The first term is a=20a = 20.
    The nn-th term of an AP is given by Tn=a+(n−1)dT_n = a + (n-1)d, where dd is the common difference.
    The third term is T3=a+(3−1)d=a+2dT_3 = a + (3-1)d = a + 2d.
    The fifth term is T5=a+(5−1)d=a+4dT_5 = a + (5-1)d = a + 4d.

  7. Set up the equation based on the given condition.

    We are given that the fifth term is four-fifth of the third term:

    T5=45T3T_5 = \frac{4}{5} T_3 a+4d=45(a+2d)a + 4d = \frac{4}{5}(a + 2d)
  8. Substitute the value of aa and solve for dd.

    Substitute a=20a = 20 into the equation:

    20+4d=45(20+2d)20 + 4d = \frac{4}{5}(20 + 2d)

    Multiply both sides by 5 to eliminate the fraction:

    5(20+4d)=4(20+2d)5(20 + 4d) = 4(20 + 2d) 100+20d=80+8d100 + 20d = 80 + 8d

    Subtract 8d8d from both sides and subtract 100 from both sides:

    20d−8d=80−10020d - 8d = 80 - 100 12d=−2012d = -20 d=−2012d = \frac{-20}{12} d=−53d = -\frac{5}{3}

    The correct option is D.

    D. −53\boxed{\text{D. } -\frac{5}{3}}

    13. Rounding to three significant figures

  9. Identify the first three significant figures in the number 6.02517.

    The significant figures are counted from the first non-zero digit.
    1st significant figure: 6
    2nd significant figure: 0
    3rd significant figure: 2

  10. Look at the fourth significant figure to determine rounding.

    The fourth significant figure is 5.
    Since the fourth significant figure (5) is 5 or greater, we round up the third significant figure.

  11. Round the number.

    Rounding up the 2 (the third significant figure) makes it 3.
    So, 6.02517 rounded to three significant figures is 6.03.

    The correct option is B.

    B. 6.03\boxed{\text{B. } 6.03}
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