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An arithmetic progression has a common difference of -2 bpm. If the heart rate at the 24th hour is 68 bpm, what is the heart rate at the 19th hour?

Mathematics

ScanSolve AI Answer

Answer

78 bpm\text{78 bpm}

Step-by-step solution

3 steps
  1. Identify the given values.

    The heart rate at the 24th hour is 68 beats per minute (bpm). We can denote this as a24=68a_{24} = 68.
    The heart rate is decreasing by 2 bpm each hour. This means the common difference d=−2d = -2 bpm.
    We need to find the heart rate 5 hours before the 24th hour, which is at hour 24−5=1924 - 5 = 19. So, we need to find a19a_{19}.

  2. Use the formula for the nn-th term of an arithmetic progression.

    The formula for the nn-th term of an arithmetic progression, given a kk-th term, is:

    an=ak+(n−k)da_n = a_k + (n-k)d
  3. Substitute the known values into the formula.

    We want to find a19a_{19}, and we know a24a_{24}. So, let n=19n=19 and k=24k=24.

    a19=a24+(19−24)da_{19} = a_{24} + (19 - 24)d a19=68+(−5)(−2)a_{19} = 68 + (-5)(-2) a19=68+10a_{19} = 68 + 10 a19=78a_{19} = 78

    The heart rate at the 19th hour is 78 bpm\boxed{\text{78 bpm}}.

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