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Determine the area of the following, in some cases leave the answer in terms of x: (DO NOT MEASURE THE DIAGRAM)

Mathematics

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Here are the solutions for the given geometry problem:

1.1 Determine the area of the following:

1.1.1 ABJH
ABJH is a square with side length xx.

  1. Identify the shape and its dimensions.

    ABJH is a square with side s=xs = x units.

  2. Apply the area formula for a square.

    Area =s2=x×x=x2= s^2 = x \times x = x^2 units2^2.

    \boxed{\text{x^2 units^2}}

    1.1.2 BCDJ
    BCDJ is a rectangle.

  3. Identify the shape and its dimensions.

    BCDJ is a rectangle with length BC=6BC = 6 units and width BJ=xBJ = x units (since ABJH is a square, BJ=AB=xBJ = AB = x).

  4. Apply the area formula for a rectangle.

    Area =length×width=BC×BJ=6×x=6x= \text{length} \times \text{width} = BC \times BJ = 6 \times x = 6x units2^2.

    \boxed{\text{6x units^2}}

    1.1.3 DEFJ
    DEFJ is a rectangle.

  5. Identify the shape and its dimensions.

    DEFJ is a rectangle. From the diagram, JD=BC=6JD = BC = 6 units.
    The total height CE=AG=AH+HG=x+4CE = AG = AH + HG = x + 4 units.
    Also, CE=CD+DECE = CD + DE. Since CD=BJ=xCD = BJ = x units, we have x+4=x+DEx + 4 = x + DE, which means DE=4DE = 4 units.

  6. Apply the area formula for a rectangle.

    Area =length×width=JD×DE=6×4=24= \text{length} \times \text{width} = JD \times DE = 6 \times 4 = 24 units2^2.

    \boxed{\text{24 units^2}}

    1.1.4 HJFG
    HJFG is a rectangle.

  7. Identify the shape and its dimensions.

    HJFG is a rectangle with length JH=xJH = x units (since ABJH is a square, JH=AH=xJH = AH = x) and width HG=4HG = 4 units.

  8. Apply the area formula for a rectangle.

    Area =length×width=JH×HG=x×4=4x= \text{length} \times \text{width} = JH \times HG = x \times 4 = 4x units2^2.

    \boxed{\text{4x units^2}}

    1.2 Write in terms of xx, the length of:

    1.2.1 AC

  9. Identify the segments that make up AC.

    The length AC is the sum of segments AB and BC.

  10. Substitute the given lengths.

    AC=AB+BC=x+6AC = AB + BC = x + 6 units.

    (x + 6) units\boxed{\text{(x + 6) units}}

    1.2.2 AG

  11. Identify the segments that make up AG.

    The length AG is the sum of segments AH and HG.

  12. Substitute the given lengths.

    AG=AH+HG=x+4AG = AH + HG = x + 4 units.

    (x + 4) units\boxed{\text{(x + 4) units}}
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