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Based on the Grade 8 revision trends, would you classify these resulting shapes as linear or non-linear? Justify your answer briefly.

Mathematics

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Here are the solutions for the remaining tasks.

Task 2.2: Classification [2 Marks]

  • Answer: The resulting shapes are linear. This is because all three equations (y=12x+2y = \frac{1}{2}x + 2, y=2x−4y = 2x - 4, and y=−2x+2y = -2x + 2) are in the form y=mx+cy = mx + c, which is the general equation for a straight line.

Task 3.1: Visual Identification [4 Marks]

Equationy-intercept (Ordered Pair)x-intercept (Ordered Pair)
Eq 1: y=12x+2y = \frac{1}{2}x + 2(0; 2)(-4; 0)
Eq 2: y=2x−4y = 2x - 4(0; -4)(2; 0)
Eq 3: y=−2x+2y = -2x + 2(0; 2)(1; 0)

Task 3.2: Algebraic Verification (Equation 2) [6 Marks]

Workspace for Equation 2 (y=2x−4y = 2x - 4):

  1. Calculate the value of y when x = 0:
  1. Substitute x=0x = 0 into the equation.

    $$
    y = 2(0) - 4
    $$
    
  2. Multiply.

    $$
    y = 0 - 4
    $$
    
  3. Subtract.

    $$
    y = \boxed{-4}
    $$
    

    2. Solve for the value of x when y = 0:

  4. Substitute y=0y = 0 into the equation.

    $$
    0 = 2x - 4
    $$
    
  5. Add 4 to both sides.

    $$
    4 = 2x
    $$
    
  6. Divide by 2.

    $$
    x = \boxed{2}
    $$
    

    Task 3.3: Synthesis of Intercepts [2 Marks]

    • Answer: When the value "0" appears in a coordinate pair, it indicates that the point lies on one of the axes. If the x-coordinate is 0 (e.g., (0,y)(0, y)), the point is on the y-axis. If the y-coordinate is 0 (e.g., (x,0)(x, 0)), the point is on the x-axis.
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