Bayangan segitiga ABC dengan koordinat A(-3, 2), B(-2,2) dan C(2,2) ditranslasikan terhadap T[3, -4], kemudian direfleksikan terhadap sumbu x adalah....

The triangle is translated by the vector $T = \begin{bmatrix} 3 \\ -4 \end{bmatrix}$.
A translation of a point $(x, y)$ by a vector $\begin{bmatrix} a \\ b \end{bmatrix}$ results in the point $(x+a, y+b)$.

Applying the translation to each vertex:
For point $A(-3, 2)$:
$A' = (-3+3, 2-4) = (0, -2)$

For point $B(-2, 2)$:
$B' = (-2+3, 2-4) = (1, -2)$

For point $C(2, 2)$:
$C' = (2+3, 2-4) = (5, -2)$

So, after the translation, the coordinates are $A'(0, -2)$, $B'(1, -2)$, and $C'(5, -2)$.

The translated triangle is then reflected across the x-axis.
A reflection of a point $(x, y)$ across the x-axis results in the point $(x, -y)$.

Applying the reflection to the translated vertices:
For point $A'(0, -2)$:
$A'' = (0, -(-2)) = (0, 2)$

For point $B'(1, -2)$:
$B'' = (1, -(-2)) = (1, 2)$

For point $C'(5, -2)$:
$C'' = (5, -(-2)) = (5, 2)$

The final coordinates of the image of triangle ABC are $A''(0, 2)$, $B''(1, 2)$, and $C''(5, 2)$.

Comparing these coordinates with the given options:
a. $A'(0, -2), B'(1, -2)$ dan $C'(5, -2)$
b. $A'(5, -2), B'(-1, -2)$ dan $C'(5, -2)$
c. $A'(0, 2), B'(1, 2)$ dan $C'(5, 2)$
d. $A'(0, -2), B'(1, -2)$ dan $C'(-5, -2)$
e. $A'(3, -2), B'(1, 2)$ dan $C'(5, -2)$

The calculated final coordinates match option c.

The final answer is $\boxed{\text{c. } A'(0, 2), B'(1, 2) \text{ dan } C'(5, 2)}$.