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How can factoring by grouping be used to express a polynomial as a product of two binomials?

Mathematics

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2 parts
2.6
5
6
3.1

2 and 32 \text{ and } 3

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3 steps

2.5 To express a polynomial as a product of two binomials after factoring by grouping, you use the distributive property. If you have an expression like x2(x+2)+3(x+2)x^2(x + 2) + 3(x + 2), the common factor is (x+2)(x + 2). You factor this common binomial out:

x2(x+2)+3(x+2)=(x+2)(x2+3)x^2(x + 2) + 3(x + 2) = (x + 2)(x^2 + 3)

This results in a product of two binomials.

Part 2.6· 3 steps

Joseph wants to factor an algebraic expression (not visible). Here is a three-step guide for factoring by grouping, which is often used for four-term polynomials

  1. Group the terms.* Divide the four-term polynomial into two pairs of terms.

    For example, (ax3+bx2)+(cx+d)(ax^3 + bx^2) + (cx + d).

  2. Factor out the greatest common factor (GCF) from each group.* This should result in a common binomial factor in both groups.

    For example, x2(ax+b)+c(ax+b)x^2(ax + b) + c(ax + b).

  3. Factor out the common binomial factor.* Use the distributive property to factor out the common binomial, expressing the polynomial as a product of two binomials.

    For example, (ax+b)(x2+c)(ax + b)(x^2 + c).

    ACTIVITY 3

    3.1.1 The table in 3.1.2 indicates that we are looking for two integers whose product is 6 and whose sum is 5. For a trinomial in the form x2+bx+cx^2 + bx + c, the product of the two integers is cc and their sum is bb.
    Therefore, the values of bb and cc in the trinomial are:
    b=5b = \boxed{5}
    c=6c = \boxed{6}

Part 3.1

2 and 32 \text{ and } 3

2** Use the table below to determine the two integers. We need two integers whose product is 6 and whose sum is 5.

Factors of 6Product of the two factorsSum of the two factorsResult
1 and 61×6=61 \times 6 = 61+6=71 + 6 = 7No
2 and 32×3=62 \times 3 = 62+3=52 + 3 = 5Yes
-1 and -6(−1)×(−6)=6(-1) \times (-6) = 6−1+(−6)=−7-1 + (-6) = -7No
-2 and -3(−2)×(−3)=6(-2) \times (-3) = 6−2+(−3)=−5-2 + (-3) = -5No

The two integers are 2 and 3\boxed{2 \text{ and } 3}.

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