This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Here are the solutions to the math problems. Q1. Write in words / Write in numbers: 1) 22, 05, 02, 038 Twenty-two crore five lakh two thousand thirty-eight. 2) Thirteen crore two lakh eighty thousand nine hundred fifty-six 13,02,80,956 Q2. Divide: 1) (25m^4 - 15m^3) ÷ 5m Step 1: Divide each term in the numerator by the denominator. (25m^4 - 15m^3)/(5m) = (25m^4)/(5m) - (15m^3)/(5m) Step 2: Simplify each term using the exponent rule (a^x)/(a^y) = a^x-y. (25m^4)/(5m) = 5m^4-1 = 5m^3 (15m^3)/(5m) = 3m^3-1 = 3m^2 Step 3: Combine the simplified terms. 5m^3 - 3m^2 The final answer is 5m^3 - 3m^2. 2) (y^3 + 0y^2 + 0y + 216) ÷ (y+6) Step 1: Recognize the numerator as a sum of cubes, y^3 + 216. Note that 216 = 6^3. So, the expression is y^3 + 6^3. Step 2: Apply the sum of cubes formula: a^3 + b^3 = (a+b)(a^2 - ab + b^2). Here, a=y and b=6. y^3 + 6^3 = (y+6)(y^2 - (y)(6) + 6^2) y^3 + 6^3 = (y+6)(y^2 - 6y + 36) Step 3: Substitute this back into the division problem. ((y+6)(y^2 - 6y + 36))/((y+6)) Step 4: Cancel out the common factor (y+6) from the numerator and denominator. y^2 - 6y + 36 The final answer is y^2 - 6y + 36. Last free one today — make it count tomorrow, or type /upgrade for unlimited.