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Convert the weight of tomatoes from a mixed fraction to an improper fraction.

Mathematics

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Here are the solutions to the problems:

  1. Bari bought 2122\frac{1}{2} kg of tomatoes and he also bought onions that were 3 times the weight of tomatoes. Find the weight of onions.
  1. Convert the weight of tomatoes from a mixed fraction to an improper fraction.

    $$
    2\frac{1}{2} \text{ kg} = \frac{(2 \times 2) + 1}{2} \text{ kg} = \frac{5}{2} \text{ kg}
    $$
    
  2. Calculate the weight of onions, which is 3 times the weight of tomatoes.

    $$
    \text{Weight of onions} = 3 \times \frac{5}{2} \text{ kg} = \frac{15}{2} \text{ kg}
    $$
    $$
    \text{Weight of onions} = 7.5 \text{ kg}
    $$
    The weight of onions is $\boxed{\text{7.5 kg}}$.
    

    2. Harish had 30 pieces of sweets. If he ate 710\frac{7}{10} of them in one week, how many pieces of sweets did he eat?

  3. Calculate the number of sweets Harish ate.

    $$
    \text{Sweets eaten} = \frac{7}{10} \times 30
    $$
    $$
    \text{Sweets eaten} = 7 \times \frac{30}{10}
    $$
    $$
    \text{Sweets eaten} = 7 \times 3
    $$
    $$
    \text{Sweets eaten} = 21
    $$
    Harish ate $\boxed{\text{21 pieces}}$ of sweets.
    

    3. In a school, there are 480 children. If 13\frac{1}{3} of them are boys, find the number of boys.

  4. Calculate the number of boys.

    $$
    \text{Number of boys} = \frac{1}{3} \times 480
    $$
    $$
    \text{Number of boys} = \frac{480}{3}
    $$
    $$
    \text{Number of boys} = 160
    $$
    The number of boys is $\boxed{\text{160}}$.
    

    4. A student lives 5 km from the school. He travels 35\frac{3}{5} km of the total distance by bus and walks the remaining distance. How far does he travel by bus?

  5. Calculate the distance traveled by bus.

    $$
    \text{Distance by bus} = \frac{3}{5} \times 5 \text{ km}
    $$
    $$
    \text{Distance by bus} = 3 \text{ km}
    $$
    The student travels $\boxed{\text{3 km}}$ by bus.
    

    5. A cylindrical rod of length 151515\frac{1}{5} m is cut into 12 pieces. Find the length of each piece.

  6. Convert the total length of the rod from a mixed fraction to an improper fraction.

    $$
    15\frac{1}{5} \text{ m} = \frac{(15 \times 5) + 1}{5} \text{ m} = \frac{75 + 1}{5} \text{ m} = \frac{76}{5} \text{ m}
    $$
    
  7. Divide the total length by the number of pieces to find the length of each piece.

    $$
    \text{Length of each piece} = \frac{76}{5} \text{ m} \div 12
    $$
    $$
    \text{Length of each piece} = \frac{76}{5} \times \frac{1}{12} \text{ m}
    $$
    $$
    \text{Length of each piece} = \frac{76}{60} \text{ m}
    $$
    
  8. Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 4.

    $$
    \text{Length of each piece} = \frac{76 \div 4}{60 \div 4} \text{ m} = \frac{19}{15} \text{ m}
    $$
    $$
    \text{Length of each piece} = 1\frac{4}{15} \text{ m}
    $$
    The length of each piece is $\boxed{\frac{19}{15} \text{ m}}$ or $\boxed{1\frac{4}{15} \text{ m}}$.
    
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