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Convert the word form number "eight million eight thousand and eighty eight" to figure and identify the place value of digit 7 in 57396. Also, calculate the remaining fraction of an apple.

Mathematics

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  1. Solve Question 1.

    The number "eight million eight thousand and eighty eight" can be broken down as:
    Eight million: 8,000,000
    Eight thousand: 8,000
    Eighty eight: 88
    Adding these values together:

    8,000,000+8,000+88=8,008,0888,000,000 + 8,000 + 88 = 8,008,088

    The number in symbols is 8,008,088.

    The final answer is D. 8008088\boxed{\text{D. } 8008088}.

  2. Solve Question 2.

    The number of crates is 57396.
    We need to find the value represented by the digit 7.
    In the number 57396:

    • The digit 6 is in the ones place.
    • The digit 9 is in the tens place.
    • The digit 3 is in the hundreds place.
    • The digit 7 is in the thousands place.
    • The digit 5 is in the ten thousands place. The digit 7 is in the thousands place, so it represents 7×1000=70007 \times 1000 = 7000.

    The final answer is C. Seven thousand\boxed{\text{C. Seven thousand}}.

  3. Solve Question 3.

    Edith gave 12\frac{1}{2} of an apple to her son and 16\frac{1}{6} to her grandson.
    First, find the total fraction of the apple given away:

    12+16\frac{1}{2} + \frac{1}{6}

    To add these fractions, find a common denominator, which is 6.

    12=1×32×3=36\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6}

    Now add the fractions:

    36+16=3+16=46\frac{3}{6} + \frac{1}{6} = \frac{3+1}{6} = \frac{4}{6}

    This is the fraction given away. To find the fraction Edith remained with, subtract this from 1 (the whole apple):

    1−46=66−46=261 - \frac{4}{6} = \frac{6}{6} - \frac{4}{6} = \frac{2}{6}

    Simplify the fraction:

    26=13\frac{2}{6} = \frac{1}{3}

    Edith remained with 13\frac{1}{3} of the apple.

    The final answer is B. 13\boxed{\text{B. } \frac{1}{3}}.

  4. Solve Question 4.

    The total amount contributed was sh. 3610.
    There were 38 boys, and each contributed an equal amount.
    To find how much each boy contributed, divide the total amount by the number of boys:

    Amount per boy=Total amountNumber of boys\text{Amount per boy} = \frac{\text{Total amount}}{\text{Number of boys}} Amount per boy=361038\text{Amount per boy} = \frac{3610}{38}

    Perform the division:

    3610÷38=953610 \div 38 = 95

    Each boy contributed sh. 95.

    The final answer is D. sh. 95\boxed{\text{D. sh. } 95}.

  5. Solve Question 5.

    A butcher bought 44 kg of meat.
    Each customer bought 14\frac{1}{4} kg of meat.
    To find the number of customers, divide the total amount of meat by the amount each customer bought:

    Number of customers=Total meatMeat per customer\text{Number of customers} = \frac{\text{Total meat}}{\text{Meat per customer}} Number of customers=4414\text{Number of customers} = \frac{44}{\frac{1}{4}}

    Dividing by a fraction is equivalent to multiplying by its reciprocal:

    Number of customers=44×4\text{Number of customers} = 44 \times 4 Number of customers=176\text{Number of customers} = 176

    There were 176 customers.

    The final answer is C. 176\boxed{\text{C. } 176}.

  6. Solve Question 6.

    The perimeter of the rectangle is P=74P = 74 cm.
    The width of the rectangle is w=15w = 15 cm.
    The formula for the perimeter of a rectangle is P=2(l+w)P = 2(l + w), where ll is the length and ww is the width.
    Substitute the given values into the formula:

    74=2(l+15)74 = 2(l + 15)

    Divide both sides by 2:

    742=l+15\frac{74}{2} = l + 15 37=l+1537 = l + 15

    Subtract 15 from both sides to find ll:

    l=37−15l = 37 - 15 l=22 cml = 22 \text{ cm}

    The length of the rectangle is 22 cm.

    The final answer is D. 22cm\boxed{\text{D. } 22\text{cm}}.

  7. Solve Question 7.

    We need to find the smallest number that can be arranged in groups of 12, 15, and 18 without a remainder. This is equivalent to finding the Least Common Multiple (LCM) of 12, 15, and 18.
    First, find the prime factorization of each number:

    12=2×2×3=22×3112 = 2 \times 2 \times 3 = 2^2 \times 3^1 15=3×5=31×5115 = 3 \times 5 = 3^1 \times 5^1 18=2×3×3=21×3218 = 2 \times 3 \times 3 = 2^1 \times 3^2

    To find the LCM, take the highest power of each prime factor present in any of the numbers:

    • For prime factor 2: The highest power is 222^2 (from 12).
    • For prime factor 3: The highest power is 323^2 (from 18).
    • For prime factor 5: The highest power is 515^1 (from 15). Multiply these highest powers together to get the LCM:
    LCM(12,15,18)=22×32×51\text{LCM}(12, 15, 18) = 2^2 \times 3^2 \times 5^1 LCM=4×9×5\text{LCM} = 4 \times 9 \times 5 LCM=36×5\text{LCM} = 36 \times 5 LCM=180\text{LCM} = 180

    The smallest number is 180.

    The final answer is A. 180\boxed{\text{A. } 180}.

  8. Solve Question 8.

    We need to estimate the quotient of 6243 and 17 by first rounding off the numbers to the nearest tens.
    Round 6243 to the nearest tens: The digit in the ones place is 3, which is less than 5, so we round down.
    6243≈62406243 \approx 6240
    Round 17 to the nearest tens: The digit in the ones place is 7, which is 5 or greater, so we round up.
    17≈2017 \approx 20
    Now, estimate the quotient:

    Quotient=624020\text{Quotient} = \frac{6240}{20} Quotient=6242\text{Quotient} = \frac{624}{2} Quotient=312\text{Quotient} = 312

    The estimated quotient is 312.

    The final answer is B. 312\boxed{\text{B. } 312}.

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