Count the strawberries and solve the addition problems.

• For $1 + 56$: $$1 + 56 = \boxed{57}$$
• For $3 + 45$: $$3 + 45 = \boxed{48}$$
• For $3 + 43$: $$3 + 43 = \boxed{46}$$
• For $2 + 34$: $$2 + 34 = \boxed{36}$$
• For $1 + 38$: $$1 + 38 = \boxed{39}$$

First, add the ones digits: $3 + 1 = 4$.
Next, add the tens digits: $2 + 4 = 6$.
The sum is 64.

There are two groups of strawberries.
The left group has 4 rows with 6 strawberries in each row, so $4 \times 6 = 24$ strawberries.
The right group also has 4 rows with 6 strawberries in each row, so $4 \times 6 = 24$ strawberries.
The total number of strawberries is $24 + 24 = \boxed{48}$.