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Find the derivative of y = e^ x

Mathematics

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Answer

etan⁡xsec⁡2xe^{\tan x} \sec^2 x

Graph of y = e^x

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Key points of y = e^x
Pointxy
y-intercept01

Step-by-step solution

5 steps

To find the derivative of y=etan⁡xy = e^{\tan x}, we use the chain rule.

  1. Identify the outer and inner functions.

    Let u=tan⁡xu = \tan x.
    Then y=euy = e^u.

  2. Differentiate yy with respect to uu.

    dydu=ddu(eu)=eu\frac{dy}{du} = \frac{d}{du}(e^u) = e^u
  3. Differentiate uu with respect to xx.

    dudx=ddx(tan⁡x)=sec⁡2x\frac{du}{dx} = \frac{d}{dx}(\tan x) = \sec^2 x
  4. Apply the chain rule, which states dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}.

    dydx=eu⋅sec⁡2x\frac{dy}{dx} = e^u \cdot \sec^2 x
  5. Substitute u=tan⁡xu = \tan x back into the expression.

    dydx=etan⁡x⋅sec⁡2x\frac{dy}{dx} = e^{\tan x} \cdot \sec^2 x

    The final answer is etan⁡xsec⁡2xe^{\tan x} \sec^2 x.

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