How did you get the 3a-2.1/2 =8 explain

Mathematics

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You're asking how 3a−2b=83a - 2b = 8 becomes 3a−2⋅12=83a - 2 \cdot \frac{1}{2} = 8.

This is the substitution step. We were given that the value of bb is 12\frac{1}{2}.
So, in the expression 3a−2b3a - 2b, we replace the variable bb with its numerical value, 12\frac{1}{2}.

When you have 2b2b, it means 2×b2 \times b.
So, when b=12b = \frac{1}{2}, then 2b2b becomes 2×122 \times \frac{1}{2}.

Therefore, 3a−2b=83a - 2b = 8 becomes:

3a−2×12=83a - 2 \times \frac{1}{2} = 8

or

3a−2(12)=83a - 2\left(\frac{1}{2}\right) = 8

Both notations mean the same thing: 2 multiplied by 12\frac{1}{2}.

Then, we perform the multiplication:

2×12=21×12=2×11×2=22=12 \times \frac{1}{2} = \frac{2}{1} \times \frac{1}{2} = \frac{2 \times 1}{1 \times 2} = \frac{2}{2} = 1

So the equation simplifies to:

3a−1=83a - 1 = 8

This is how we get to that step.

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