Divide the LCM of 160,18,24 by their HCF

Mathematics

ScanSolve AI Answer

Answer

720

Step-by-step solution

4 steps
  1. Find the prime factorization of each number.

    160=16×10=24×(2×5)=25×51160 = 16 \times 10 = 2^4 \times (2 \times 5) = 2^5 \times 5^1 18=2×9=21×3218 = 2 \times 9 = 2^1 \times 3^2 24=8×3=23×3124 = 8 \times 3 = 2^3 \times 3^1
  2. Calculate the HCF (Highest Common Factor).

    The HCF is found by taking the lowest power of each common prime factor.
    The only common prime factor among 160,18,160, 18, and 24 is 2.
    The lowest power of 2 is 212^1 (from 18).

    HCF(160,18,24)=21=2\text{HCF}(160, 18, 24) = 2^1 = 2
  3. Calculate the LCM (Least Common Multiple).

    The LCM is found by taking the highest power of each prime factor present in any of the numbers.

    • Highest power of 2: 252^5 (from 160)
    • Highest power of 3: 323^2 (from 18)
    • Highest power of 5: 515^1 (from 160)
    LCM(160,18,24)=25×32×51\text{LCM}(160, 18, 24) = 2^5 \times 3^2 \times 5^1 LCM=32×9×5\text{LCM} = 32 \times 9 \times 5 LCM=288×5\text{LCM} = 288 \times 5 LCM=1440\text{LCM} = 1440
  4. Divide the LCM by the HCF.

    LCMHCF=14402\frac{\text{LCM}}{\text{HCF}} = \frac{1440}{2} LCMHCF=720\frac{\text{LCM}}{\text{HCF}} = 720

    The result of dividing the LCM by the HCF is 720.

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