We read your photo as:

Calculate the duration between the following pairs of times: 1) 2:15 p.m. to 2:50 p.m., 2) 1:20 p.m. to 2:30 p.m., 3) 2:25 p.m. to 3:10 p.m.

Mathematics

ScanSolve AI Answer

Step-by-step solution

5 steps

Here are the durations for each pair of times:

1. Duration from 2:15 p.m. to 2:50 p.m.

  1. Subtract the start time from the end time.

    2 hours 50 minutes−2 hours 15 minutes2 \text{ hours } 50 \text{ minutes} - 2 \text{ hours } 15 \text{ minutes} =(2−2) hours (50−15) minutes= (2-2) \text{ hours } (50-15) \text{ minutes} =0 hours 35 minutes= 0 \text{ hours } 35 \text{ minutes}

    The duration is 35 minutes\boxed{\text{35 minutes}}.

    2. Duration from 1:20 p.m. to 2:30 p.m.

  2. Calculate the time from 1:20 p.m.

    to 2:00 p.m.

    2 hours 00 minutes−1 hour 20 minutes2 \text{ hours } 00 \text{ minutes} - 1 \text{ hour } 20 \text{ minutes} =(1 hour 60 minutes)−(1 hour 20 minutes)= (1 \text{ hour } 60 \text{ minutes}) - (1 \text{ hour } 20 \text{ minutes}) =40 minutes= 40 \text{ minutes}
  3. Add the remaining time from 2:00 p.m.

    to 2:30 p.m.

    40 minutes+30 minutes=70 minutes40 \text{ minutes} + 30 \text{ minutes} = 70 \text{ minutes}

    Alternatively, this is 1 hour and 10 minutes.
    The duration is 1 hour 10 minutes\boxed{\text{1 hour 10 minutes}}.

    3. Duration from 2:25 p.m. to 3:10 p.m.

  4. Calculate the time from 2:25 p.m.

    to 3:00 p.m.

    3 hours 00 minutes−2 hours 25 minutes3 \text{ hours } 00 \text{ minutes} - 2 \text{ hours } 25 \text{ minutes} =(2 hours 60 minutes)−(2 hours 25 minutes)= (2 \text{ hours } 60 \text{ minutes}) - (2 \text{ hours } 25 \text{ minutes}) =35 minutes= 35 \text{ minutes}
  5. Add the remaining time from 3:00 p.m.

    to 3:10 p.m.

    35 minutes+10 minutes=45 minutes35 \text{ minutes} + 10 \text{ minutes} = 45 \text{ minutes}

    The duration is 45 minutes\boxed{\text{45 minutes}}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question