![E[Y] = 11 ((11)/(120)) + (4)/(3)](/_next/image?url=https%3A%2F%2Fohijasnjvprzodcmxltt.supabase.co%2Fstorage%2Fv1%2Fobject%2Fpublic%2Fwhatsapp-images%2F1777009415738-7701efc98c1749ae.png&w=3840&q=75)
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
E[Y] = 11 ((11)/(120)) + (4)/(3) E[Y] = (121)/(120) + (4)/(3) To add these fractions, find a common denominator, which is 120: E[Y] = (121)/(120) + (4 × 40)/(3 × 40) E[Y] = (121)/(120) + (160)/(120) E[Y] = (121 + 160)/(120) E[Y] = (281)/(120) Now, calculate E[2Y + 4] using the property E[aY + b] = aE[Y] + b: E[2Y + 4] = 2E[Y] + 4 Substitute the value of E[Y]: E[2Y + 4] = 2 ((281)/(120)) + 4 E[2Y + 4] = (2 × 281)/(120) + 4 E[2Y + 4] = (562)/(120) + 4 Simplify the fraction (562)/(120) by dividing both numerator and denominator by 2: E[2Y + 4] = (281)/(60) + 4 Convert 4 to a fraction with a denominator of 60: E[2Y + 4] = (281)/(60) + (4 × 60)/(60) E[2Y + 4] = (281)/(60) + (240)/(60) E[2Y + 4] = (281 + 240)/(60) E[2Y + 4] = (521)/(60) The value of E[2Y + 4] is (521)/(60). That's 2 down. 3 left today — send the next one.