Solve the equation (2x5)(x+3)=0

For the equation $(2x-5)(x+3)=0$, we set each term in the parentheses to zero.

$$2x-5=0 \quad \text{or} \quad x+3=0$$

Add 5 to both sides of the first equation.

$$2x = 5$$

Divide by 2.

$$x = \frac{5}{2}$$

Subtract 3 from both sides of the second equation.

$$x = -3$$

The solutions are $x = \frac{5}{2}$ and $x = -3$.

$$x = \frac{5}{2}, x = -3$$