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Solve the equation 3x2 − 17x − 6 = 0 using factorization method

Mathematics

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Answer

3\textbf{3}

Step-by-step solution

6 steps
  1. Andika nambari zote kama nguvu za 2.

    32=2532 = 2^5 8=238 = 2^3 64=2664 = 2^6
  2. Badilisha nambari hizi kwenye mlinganyo.

    (25)(x−3)÷(23)(x−4)=26÷2x(2^5)^{(x-3)} \div (2^3)^{(x-4)} = 2^6 \div 2^x
  3. Tumia sheria ya nguvu (am)n=amn(a^m)^n = a^{mn}.

    25(x−3)÷23(x−4)=26÷2x2^{5(x-3)} \div 2^{3(x-4)} = 2^6 \div 2^x 25x−15÷23x−12=26÷2x2^{5x-15} \div 2^{3x-12} = 2^6 \div 2^x
  4. Tumia sheria ya kugawanya am÷an=am−na^m \div a^n = a^{m-n}.

    2(5x−15)−(3x−12)=26−x2^{(5x-15) - (3x-12)} = 2^{6-x} 25x−15−3x+12=26−x2^{5x-15-3x+12} = 2^{6-x} 22x−3=26−x2^{2x-3} = 2^{6-x}
  5. Linganisha viashiria vya nguvu kwa sababu besi ni sawa.

    2x−3=6−x2x-3 = 6-x
  6. Tatua kwa xx.

    2x+x=6+32x+x = 6+3 3x=93x = 9 x=93x = \frac{9}{3} x=3x = \boxed{\textbf{3}}
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