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Find the equation of a line with gradient 3 that passes through the point (2, 1).

Mathematics

ScanSolve AI Answer

Answer

y=3x−5y = 3x - 5

Step-by-step solution

3 steps
  1. Identify the given information.

    The gradient (slope) m=3m = 3.
    The line passes through the point (x1,y1)=(2,1)(x_1, y_1) = (2, 1).

  2. Use the point-slope form of a linear equation, which is y−y1=m(x−x1)y - y_1 = m(x - x_1).

    Substitute the given values into the formula:

    y−1=3(x−2)y - 1 = 3(x - 2)
  3. Simplify the equation to the slope-intercept form y=mx+cy = mx + c.

    Distribute the gradient on the right side:

    y−1=3x−6y - 1 = 3x - 6

    Add 1 to both sides of the equation:

    y=3x−6+1y = 3x - 6 + 1 y=3x−5y = 3x - 5

    The equation of the line is y = 3x - 5.

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