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Write the equivalent logarithmic statement for 53 = 125 and the equivalent exponential statement for 5 (1)/(5) = -1.
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Write the equivalent logarithmic statement for each of the following:
a)
Identify the base, exponent, and result.
Base $= 5$, Exponent $= 3$, Result $= 125$.Apply the logarithmic definition
If , then . The equivalent logarithmic statement is .
**b)** $y^x = z$Identify the base, exponent, and result.
Base $= y$, Exponent $= x$, Result $= z$.Apply the logarithmic definition
If , then . The equivalent logarithmic statement is .
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Write the equivalent exponential statement for each of the following:
a)
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Identify the base, logarithm value, and result.
Base $= 5$, Logarithm value $= -1$, Result $= \frac{1}{5}$.Apply the exponential definition
If , then . The equivalent exponential statement is .
**b)** $\log_9 3 = \frac{1}{2}$Identify the base, logarithm value, and result.
Base $= 9$, Logarithm value $= \frac{1}{2}$, Result $= 3$.Apply the exponential definition
If , then . The equivalent exponential statement is .
**c)** $\log_5 625 = 4$Identify the base, logarithm value, and result.
Base $= 5$, Logarithm value $= 4$, Result $= 625$.Apply the exponential definition
If , then . The equivalent exponential statement is .
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Solve for in the following exponential equations:
a)
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Express both sides with the same base.
$$ 2^{x-1} = 2^6 $$Equate the exponents.
$$ x-1 = 6 $$Solve for .
$$ x = 6+1 $$ $$ x = 7 $$ The value of $x$ is $\boxed{7}$. **b)** $49^x = \frac{1}{7}$Express both sides with the same base.
$$ (7^2)^x = 7^{-1} $$Simplify the left side using exponent rules .
$$ 7^{2x} = 7^{-1} $$Equate the exponents.
$$ 2x = -1 $$Solve for .
$$ x = -\frac{1}{2} $$ The value of $x$ is $\boxed{-\frac{1}{2}}$. **c)** $\frac{1}{2^x} = 8$Express both sides with the same base.
$$ 2^{-x} = 2^3 $$Equate the exponents.
$$ -x = 3 $$Solve for .
$$ x = -3 $$ The value of $x$ is $\boxed{-3}$.
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