Solve the exercise their

The equation to solve is $2x^2 - 8x + 6 = 0$.

$\frac{2x^2}{2} - \frac{8x}{2} + \frac{6}{2} = \frac{0}{2}$
$x^2 - 4x + 3 = 0$

We need two numbers that multiply to 3 and add to -4. These numbers are -1 and -3.
$(x - 1)(x - 3) = 0$

For the first factor:
$x - 1 = 0$
$x = 1$

For the second factor:
$x - 3 = 0$
$x = 3$

The solutions are $x = 1$ and $x = 3$.

x=1, x=3